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// S = S0 * f(L/Lmin) where f(x) = 1 + (7 * 2/Pi * atan(x/5))

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+    // The above formular gives too short segments when Lmax/Lmin is too high
+    // because by this formular the largest segment is only 8 times longer than the
+    // shortest one ( 2/Pi * atan(x/5) varies within [0,1] ). So a new formular is:
+    // f(x) = 1 + (x/7 * 2/Pi * atan(x/5))
This commit is contained in:
eap 2013-03-12 11:31:32 +00:00
parent dbd3054f4f
commit 6da7fe1a54
1 changed files with 32 additions and 17 deletions
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49
src/StdMeshers/StdMeshers_AutomaticLength.cxx
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@ -117,15 +117,29 @@ namespace {
*/
//================================================================================
const double a14divPI = 14. / M_PI;
//const double a14divPI = 14. / M_PI;
const double a2div7divPI = 2. / 7. / M_PI;
inline double segLength(double S0, double edgeLen, double minLen )
{
// PAL10237
// S = S0 * f(L/Lmin) where f(x) = 1 + (2/Pi * 7 * atan(x/5) )
// S = S0 * f(L/Lmin) where
// f(x) = 1 + (7 * 2/Pi * atan(x/5))
// =>
// S = S0 * ( 1 + 14/PI * atan( L / ( 5 * Lmin )))
return S0 * ( 1. + a14divPI * atan( edgeLen / ( 5 * minLen )));
//
// return S0 * ( 1. + a14divPI * atan( edgeLen / ( 5 * minLen )));
// The above formular gives too short segments when Lmax/Lmin is too high
// because by this formular the largest segment is only 8 times longer than the
// shortest one ( 2/Pi * atan(x/5) varies within [0,1] ). So a new formular is:
//
// f(x) = 1 + (x/7 * 2/Pi * atan(x/5))
// =>
// S = S0 * ( 1 + 2/7/PI * L/Lmin * atan( 5 * L/Lmin ))
//
const double Lratio = edgeLen / minLen;
return S0 * ( 1. + a2div7divPI * Lratio * atan( 5 * Lratio ));
}
//================================================================================
@ -164,22 +178,22 @@ namespace {
theTShapeToLengthMap.insert( make_pair( getTShape( edge ), L ));
}
// Compute S0
// Compute S0 - minimal segement length, is computed by the shortest EDGE
// image attached to PAL10237
// NbSeg
// ^
// |
// 10|\
// | \
// | \
// | \
// 5| --------
// |
// +------------>
// 1 10 Lmax/Lmin
/* image attached to PAL10237
NbSeg (on the shortest EDGE)
^
|
10|\
| \
| \
| \
5| --------
|
+------------>
1 10 Lmax/Lmin
*/
const int NbSegMin = 5, NbSegMax = 10; // on axis NbSeg
const double Lrat1 = 1., Lrat2 = 10.; // on axis Lmax/Lmin
@ -192,6 +206,7 @@ namespace {
MESSAGE( "S0 = " << S0 << ", Lmin = " << Lmin << ", Nbseg = " << (int) NbSeg);
// Compute segments length for all edges
map<const TopoDS_TShape*, double>::iterator tshape_length = theTShapeToLengthMap.begin();
for ( ; tshape_length != theTShapeToLengthMap.end(); ++tshape_length )
{