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Fix FirstVertexOnCurve(edge): use MakeVertexOnCurve() instead of

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KindOfShape() to find the EDGE beginning
This commit is contained in:
eap 2013-03-12 11:28:32 +00:00
parent 1303d07964
commit dbd3054f4f
1 changed files with 5 additions and 5 deletions
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10
src/SMESH_SWIG/smeshDC.py
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@ -276,15 +276,15 @@ def AssureGeomPublished(mesh, geom, name=''):
## Return the first vertex of a geomertical edge by ignoring orienation
def FirstVertexOnCurve(edge):
from geompy import SubShapeAll, ShapeType, KindOfShape, PointCoordinates
from geompy import SubShapeAll, ShapeType, MakeVertexOnCurve, PointCoordinates
vv = SubShapeAll( edge, ShapeType["VERTEX"])
if not vv:
raise TypeError, "Given object has no vertices"
if len( vv ) == 1: return vv[0]
info = KindOfShape(edge)
xyz = info[1:4] # coords of the first vertex
xyz1 = PointCoordinates( vv[0] )
xyz2 = PointCoordinates( vv[1] )
v0 = MakeVertexOnCurve(edge,0.)
xyz = PointCoordinates( v0 ) # coords of the first vertex
xyz1 = PointCoordinates( vv[0] )
xyz2 = PointCoordinates( vv[1] )
dist1, dist2 = 0,0
for i in range(3):
dist1 += abs( xyz[i] - xyz1[i] )